What is the wild card mask for 172.16.1.2/18?

According to the /18 analoby wild card mask will be 32-18= last 14 bits on.

w/ mask is 0.0.63.255

Convert 172.16.1.2/18 to its subnet mask of :255.255.192.0;

subtract from all 255s

i.e 255.255.255.255

-  

   255.255.192.0

=0.0.63.255

this is the WCM for the prefix and prefix lenght