Three element having conductance G1, G2 and G3 are connected in parallel. Their combined conductance will be?

Submitting more applications increases your chances of landing a job.

Here’s how busy the average job seeker was last month:

Opportunities viewed

Applications submitted

Keep exploring and applying to maximize your chances!

Looking for employers with a proven track record of hiring women?

Click here to explore opportunities now!

We Value Your Feedback

You are invited to participate in a survey designed to help researchers understand how best to match workers to the types of jobs they are searching for

Would You Be Likely to Participate?

If selected, we will contact you via email with further instructions and details about your participation.

You will receive a $7 payout for answering the survey.

Start networking and exchanging professional insights

Next Question:
Four elements each having conductance of G1, G2, G3, G4 respectively are connect...
Posted by:
karthikeyan tamizhselvan
23-February-2017

Power Plants PLC Electric Power Electrical Engineering Electrical Maintenance

Question added by muhammad arif , Assistant Engineer , Phoenix armour
Date Posted: 2013/11/23

Upvote (17) Views (22) Followers (5) Answers (6) Report Question

Write an Answer
Register now or log in to answer.

6 Answers

by muhammad arif , Assistant Engineer , Phoenix armour

G1 + G2 + G3

Upvote (15)

Downvote Reply () Report

by Safi Ullah , Electrical Trainee Engineer , PESCO (Peshawar Electric Supply Company)

The combined conductance,

G equivalent= G1+G2+G3

Upvote (1)

Downvote Reply () Report

by Khader Khan , ITC Ltd

Combined conductance will be G1 + G2 + G3

Explanation:

Conductance is invese of resistance

G =1/R

Equivalent resistance Req of three resistances R1, R2, R3 in parallel will be

1/Req =1/R1 +1/R2 +1/R3

So, Geq = G1 + G2 + G3

Upvote (1)

Downvote Reply () Report

by MANU N GOWDA

Resistance in series R= R1 +R2+R3 Resistance in parallel (1/R)= (1/R1)+(1/R2)+(1/R3) Conductance in series G=G1+G2+G3Conductance in parallel (1/G) =(1/G1)+(1/G2)+(1/G3)G=1/R Resistance in parallel (1/R)= (1/R1)+(1/R2)+(1/R3)So if u write in conductance form it will be G= G1 + G2 +G3But questions is just parallel of condcatnce so Answer will be (1/G)= (1/G1)+(1/G2)+(1/G3) Resistance parallel ckt= conducatne series ckt Resistance series ckt =conductance parallel ckt

Upvote (0)

Downvote Reply () Report