Submitting more applications increases your chances of landing a job.

Here’s how busy the average job seeker was last month:

Opportunities viewed

Applications submitted

Keep exploring and applying to maximize your chances!

Looking for employers with a proven track record of hiring women?

Click here to explore opportunities now!
We Value Your Feedback

You are invited to participate in a survey designed to help researchers understand how best to match workers to the types of jobs they are searching for

Would You Be Likely to Participate?

If selected, we will contact you via email with further instructions and details about your participation.

You will receive a $7 payout for answering the survey.


Start networking and exchanging professional insights

Register now or log in to join your professional community.

Follow

Define Time Variant And Time Invariant System?

A system is called time invariant if its output , input characteristics dos not change with time. e.g.y(n)=x(n)+x(n-1) A system is called time variant if its input, output characteristics changes with time. e.g.y(n)=x(-n).

user-image
Question added by PAPPU MAJUMDER , Microsoft Business intelligence (MSBI) , Equifax
Date Posted: 2018/01/07
Ali Mehran Khan
by Ali Mehran Khan , Engineer Electrical Maintenance , Arcelik Global

A system is called Time Invariant if we delay an input before processing, output will be equal to output delayed after processing. And if we delay an input before processing, output will not be equal to input delayed after processing, the system is Time Variant.

A more formal proof of why systems A and B above differ is now presented. To perform this proof, the second definition will be used.

System A:

Start with a delay of the input {\\displaystyle x_{d}(t)=\\,\\!x(t+\\delta )}x_{d}(t)=\\,\\!x(t+\\delta ) {\\displaystyle y(t)=t\\,x(t)}y(t)=t\\,x(t) {\\displaystyle y_{1}(t)=t\\,x_{d}(t)=t\\,x(t+\\delta )}y_{1}(t)=t\\,x_{d}(t)=t\\,x(t+\\delta ) Now delay the output by {\\displaystyle \\delta }\\delta {\\displaystyle y(t)=t\\,x(t)}y(t)=t\\,x(t) {\\displaystyle y_{2}(t)=\\,\\!y(t+\\delta )=(t+\\delta )x(t+\\delta )}y_{2}(t)=\\,\\!y(t+\\delta )=(t+\\delta )x(t+\\delta ) Clearly {\\displaystyle y_{1}(t)\\,\\!\\neq y_{2}(t)}y_{1}(t)\\,\\!\\neq y_{2}(t), therefore the system is not time-invariant.

System B:

Start with a delay of the input {\\displaystyle x_{d}(t)=\\,\\!x(t+\\delta )}x_{d}(t)=\\,\\!x(t+\\delta ) {\\displaystyle y(t)=10\\,x(t)}y(t)=10\\,x(t) {\\displaystyle y_{1}(t)=10\\,x_{d}(t)=10\\,x(t+\\delta )}y_{1}(t)=10\\,x_{d}(t)=10\\,x(t+\\delta ) Now delay the output by {\\displaystyle \\,\\!\\delta }\\,\\!\\delta {\\displaystyle y(t)=10\\,x(t)}y(t)=10\\,x(t) {\\displaystyle y_{2}(t)=y(t+\\delta )=10\\,x(t+\\delta )}y_{2}(t)=y(t+\\delta )=10\\,x(t+\\delta ) Clearly {\\displaystyle y_{1}(t)=\\,\\!y_{2}(t)}y_{1}(t)=\\,\\!y_{2}(t), therefore the system is time-invariant.

More generally, the relationship between the input and output is {\\displaystyle y(t)=f(x(t),t)}{\\displaystyle y(t)=f(x(t),t)}, and its variation with time is

{\\displaystyle {\\frac {\\mathrm {d} y}{\\mathrm {d} t}}={\\frac {\\partial f}{\\partial t}}+{\\frac {\\partial f}{\\partial x}}{\\frac {\\mathrm {d} x}{\\mathrm {d} t}}}{\\displaystyle {\\frac {\\mathrm {d} y}{\\mathrm {d} t}}={\\frac {\\partial f}{\\partial t}}+{\\frac {\\partial f}{\\partial x}}{\\frac {\\mathrm {d} x}{\\mathrm {d} t}}}.

For time-invariant systems, the system properties remain constant with time, {\\displaystyle \\partial f/\\partial t=0}{\\displaystyle \\partial f/\\partial t=0}. Applied to Systems A and B above:

{\\displaystyle f_{A}=tx(t)\\qquad \\Rightarrow \\qquad {\\frac {\\partial f_{A}}{\\partial t}}=x(t)\\neq 0}{\\displaystyle f_{A}=tx(t)\\qquad \\Rightarrow \\qquad {\\frac {\\partial f_{A}}{\\partial t}}=x(t)\\neq 0} in general, so not time-invariant {\\displaystyle f_{B}=10x(t)\\qquad \\Rightarrow \\qquad {\\frac {\\partial f_{B}}{\\partial t}}=0}{\\displaystyle f_{B}=10x(t)\\qquad \\Rightarrow \\qquad {\\frac {\\partial f_{B}}{\\partial t}}=0} so time-invariant.

Deleted user
by Deleted user

A system is called time invariant if its output , input characteristics dos not change with time.

Introduce a known delay y(n,k) to a given system and determine the output as y(n,k). As a second scenario, substitute the discrete time variable n by n-k in the given system, say y(n-k). 

If both y(n,k) = y(n-k),-------> system is time invariant. 

Otherwise, time variant

PAPPU MAJUMDER
by PAPPU MAJUMDER , Microsoft Business intelligence (MSBI) , Equifax

A system is called time invariant if its output , input characteristics dos not change with time.

e.g.y(n)=x(n)+x(n-1)

A system is called time variant if its input, output characteristics changes with time.

e.g.y(n)=x(-n).

More Questions Like This