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Four coins are thrown together,what are probability of i. At least two coin and ii. At most three coins

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Question added by Shahid Farhan , Visiting lecturer , Islamia University of Bahawalpur Pakistan
Date Posted: 2013/09/20
elonsy brahim
by elonsy brahim , teacher , cadi ayyad university

let 'S' a sample space ,then card(S)=16.

i)At last two coin : P=(2C4+3C4+4C4)/card(S)=11/16

ii)At most three coins:P=(1C4+2C4+3C4)/card(S)=14/16

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