A truck was purchased for $25,000. It has a six-year life and a $4,000 salvage value.?

Yes, Option D is the right answer.

Correct answer is a. $8,750

Carrying value is d. $16,250.

D-----------------------------------------

d. $16,250.                                                                     ....                                     

Answer is D. $16,250.

$25,000-4,000=$21,000/6=$3,500 x2.5=$8,750

$25,000-8,750=$16,250

Answer is $16250 ($25000 less depreciation after2.5 yrs $8750).

Yes option D is right answer. =21000 Now per year depreciation21000/6=3500$ so total dep of2.5 years is8750$. Total value - dep.25000 -8750=16250$

as per my view answer D is correct answer..because as per  Ias16..we can use straight line method for depreciation..in this method to calculate depreciation we deduct residual value from cost ().and then divide the remaining amount on expected useful life that is6 years here and then we get1 year depreciation and by multipling that amount with no of years past we can get current year depreciation..e.g: ($-$4000)=$21000/6=$3500 (2.5years)=$8750..$8750 is accumulated depreciation for2.5 years..so after2.5 years C.V will be $16250 ().if  i made any mistake during answer i will be happy if any1 make me correct.

Option D is the correct answer

the correct answer is : B - $12,250