Father is aged 3 times more than his son. After 8 yrs,he would be 2.5 times of Son's age. After further 8 yrs,how many times would he be of Son's age?

D.2.25yrs.

x=3x

x+8=2.5(x+8)

Let present age of father: x

Let present age of son: y

Equations will be:

x = 3y

(x+8) = 2.5(y+8)

solving these both,

answer will be:

2.25 times

let the age of son be X then father is3X

after8 years son is X+8 father will be2.5(X+8)

and the answer is2. times

Hey M. Shahad,

My answer is2.2 times