Typing on the screen contents of a variable char s = "this is only a test" will be done in C ++ using statement:

c. cout <<  s , is the correct answer

The correct answer is;

C. cout << s

Remember;

- you always "give" to cout (hence cout << aVariable;)

- you always "take" from cin (hence cin >> aVariable;)

Hey Tomasz Modrzejewski...!!

Are you alright..??

How can you forget this basic thing..

The right choice is C.

cout << s ;

yes C / how did you know ? Do you can prove it?